Метод STDisjoint
Determines whether the calling SqlGeometry instance is disjointed when compared against the specified SqlGeometry.
Пространство имен: Microsoft.SqlServer.Types
Сборка: Microsoft.SqlServer.Types (в Microsoft.SqlServer.Types.dll)
Синтаксис
'Декларация
<SqlMethodAttribute(IsDeterministic := True, IsPrecise := False)> _
Public Function STDisjoint ( _
other As SqlGeometry _
) As SqlBoolean
'Применение
Dim instance As SqlGeometry
Dim other As SqlGeometry
Dim returnValue As SqlBoolean
returnValue = instance.STDisjoint(other)
[SqlMethodAttribute(IsDeterministic = true, IsPrecise = false)]
public SqlBoolean STDisjoint(
SqlGeometry other
)
[SqlMethodAttribute(IsDeterministic = true, IsPrecise = false)]
public:
SqlBoolean STDisjoint(
SqlGeometry^ other
)
[<SqlMethodAttribute(IsDeterministic = true, IsPrecise = false)>]
member STDisjoint :
other:SqlGeometry -> SqlBoolean
public function STDisjoint(
other : SqlGeometry
) : SqlBoolean
Параметры
- other
Тип: Microsoft.SqlServer.Types. . :: . .SqlGeometry
The SqlGeometry instance to compare against the instance on which STDisjoint is invoked.
Возвращаемое значение
Тип: System.Data.SqlTypes. . :: . .SqlBoolean
Returns true if a SqlGeometry instance is spatially disjointed from another SqlGeometry instance. Returns false if it is not.
Замечания
Two SqlGeometry instances are disjointed if the intersection of their point sets is empty.
This method always returns null if the spatial reference IDs (SRIDs) of the SqlGeometry instances do not match.