To implement a web request for logging in and handling errors in Visual Basic, you can follow the structure you provided, but there are a few adjustments needed to ensure proper functionality. Here’s a refined version of your code:
Dim username As String = TxtBox_Username.Text ' Username
Dim password As String = TxtBox_Password.Text ' Password
Dim url As String = "http://hostname:8000" ' Complete URL with port
Try
Dim request As HttpWebRequest = CType(WebRequest.Create(url), HttpWebRequest) ' Create Url Hostname to Connect to the Server
request.Credentials = New NetworkCredential(username, password) ' Using Username and Password to use Credentials
Dim response As HttpWebResponse = CType(request.GetResponse(), HttpWebResponse)
Using reader As New StreamReader(response.GetResponseStream())
Dim responseText As String = reader.ReadToEnd()
Form2.Show() ' Load Form2 on successful login
Me.Hide()
End Using
response.Close()
Catch ex As WebException
Dim errorResponse As HttpWebResponse = CType(ex.Response, HttpWebResponse)
Dim Frm_Error As String = "Error: " & CType(errorResponse.StatusCode, Integer).ToString() ' Capture error status code
MessageBox.Show(Frm_Error) ' Show error message box
End Try
Key Changes:
- URL Construction: Ensure the URL includes the port directly in the string (e.g.,
"http://hostname:8000"). - Error Handling: Use a
Try...Catchblock to handle exceptions that may occur during the request. This allows you to catchWebExceptionand display the error message appropriately. - Response Handling: Ensure that you close the response in the
Finallyblock or after you are done using it to free up resources.
This structure will help you manage the login process and handle any errors effectively, displaying them in a message box as required.